(3/5)^(4-2x)=6

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Solution for (3/5)^(4-2x)=6 equation: 



(3/5)^(4-2x)=6

We move all terms to the left:

(3/5)^(4-2x)-(6)=0



Domain of the equation: 5)^(4-2x)!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)^(-2x+4)-6=0

We multiply all the terms by the denominator


(+3-6*5)^(-2x+4)=0

We add all the numbers together, and all the variables

(-27)^(-2x+4)=0

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